What is the ideal effort force for a second class lever with an effort arm of 0.80 m and a load of 180 N?

In a second class lever, the load is positioned between the effort force and the fulcrum, which allows the lever to amplify the input force. The mechanical advantage of a lever is determined by the ratio of the lengths of the effort arm to the load arm. To find the ideal effort force needed for a second class lever, one can use the principle of moments, which states that the moments around the fulcrum created by the load and the effort must be equal for the system to be in equilibrium.

The formula for calculating the ideal effort force in a lever is given by:

[ \text{Effort Force} = \frac{\text{Load} \times \text{Load Arm}}{\text{Effort Arm}} ]

In this case, we know the load is 180 N and the effort arm is 0.80 m. To find the ideal effort force, we need to establish the load arm. Since the mechanics of a second class lever means the load is in the middle, let's assume that we are focusing on a simplified scenario where the load arm is equal to the effort arm for ideal calculations unless specified otherwise.

However, if we assume the load arm for this problem to be half the effort arm (