What is the ideal effort required to lift a load of 160 N with a second class lever with an effort arm of 0.80 m and a load arm of 0.25 m?

To determine the ideal effort required to lift a load using a second-class lever, you can apply the principle of moments, which states that the load multiplied by the load arm should equal the effort multiplied by the effort arm.

In this scenario, the load is 160 N, the load arm is 0.25 m, and the effort arm is 0.80 m. Applying the formula for the lever:

Load × Load Arm = Effort × Effort Arm

Substituting the known values into the equation gives:

160 N × 0.25 m = Effort × 0.80 m

Calculating the left side, we have:

40 N·m = Effort × 0.80 m

To find the effort, divide both sides of the equation by the effort arm:

Effort = 40 N·m / 0.80 m

This simplifies to:

Effort = 50 N

Thus, the ideal effort required to lift the load of 160 N with the given lever dimensions is indeed 50 N. This is why the answer is correctly identified as the one that corresponds to this calculation.